# How to Calculate Load and Power for Symmetrical 3-Roll Plate Bending Machine

Have you ever wondered how heavy steel plates are bent into smooth curves? In this article, we delve into the fascinating world of plate bending machines. Our expert mechanical engineer will explain the key concepts behind symmetrical 3-roll plate bending and the load analysis used to calculate the required power. By the end, you’ll have a deeper appreciation for these unsung heroes of metal fabrication and the engineering marvels they create.

## Introduction

The load on plate roll bending machines is substantial, so the strength of its parts must be high.

Furthermore, with intense competition in the market, reducing the cost of plate rolls is crucial. This means that the machine must be designed with accuracy and reliability.

In order to design the roll bending machine, it is necessary to first perform a force analysis of the rolling machine, which provides the original parameters for designing each part of the machine.

The calculation of the driving power of the main drive system is also important for designing the main drive system and selecting the motor.

As a result, calculating the force analysis and driving power of the plate rolling machine is critical to the design of the roll bending machine.

This post provides one method for calculating the force capabilities of a symmetrical three-roll bending machine, and other types of plate rolling machines can use it as a reference.

## Force Analysis

### 2.1 Maximum torque required for a cylinder rolling

When the plate rolling machine is working, the steel sheet should be rolled into the steel pipe.

At this time, the stress of the material has reached the yield limit.

Therefore, the bending stress distribution on the tube section is shown below the figure (b), and the bending moment M of the section is:

In the above formula,

• B, δ – The maximum width and thickness of rolled steel sheet (m)
• σs – Material’s yield limit (kN m-2)

Fig.1 Stress distribution of roll bending

When considering the deformation of the material, there is reinforcement, and the reinforcement coefficient K is introduced to modify the equation (1), namely:

In the above formula,

• K – reinforcement coefficient, the value can be K = 1.10~1.25, when the result for δ/R is big, then take the biggest value.
• R – Neutral layer’s radius of the rolling plate (m)

### 2.2 Force Condition

When rolling steel plate, the force condition is shown as below figure. According to the force balance, the supporting force Fon the roll plate can be obtained via the formula:

In the above formula,

• θ – The angle between defiled line OO1 and OO2,
• α – Lower roller center distance (m)
• dmin – Min diameter of plate rolling (m)
• d2Lower roller diameter (m)

Fig.2 Force analysis of roll bending

Considering that the thickness of the plate δ is far less than the minimum diameter of the rolling tube, the radius R of the neutral layer is around 0.5dmin, in order to simplify the calculation, the above equation can be changed to:

According to the force balance, the pressure force F1, which is generated by the upper roller, acting on the rolling plate is:

## Calculation of driving power

### 3.1 Lower roller drive moment

The lower roller of the plate rolling machine is the driving roller, and the driving torque on the lower roller is used to overcome the deformation torque Tn1 and the friction torque Tn2.

In the process of steel plate rolling, the deformation capabilities stored in AB section of the steel plate (see Fig 1a and Fig 2) is 2Mθ, the costed time is 2θR/V (V is rolling speed).

The ratio is equal to the power of deformation torque Tn1, namely:

Therefore,

The friction torque includes the rolling friction torque between the upper and lower roller and the steel plate, and the sliding friction torque between the roller neck and the shaft sleeve, which can be calculated as follows:

In the above formula:

• f – Coefficient of rolling friction, take f = 0.008m
• μ – Coefficient of sliding friction, take μ = 0.05-0.1d1,
• d2 – Upper roller & lower roller diameter (m)
• D1, D2 – Upper roller & lower roller neck diameter (m)

The size is not yet accurate in the design phase, the value can take Di = 0.5di (i=1, 2). The lower roller drive torque T equals the sum of the deformation torque Tn1 and the friction torque Tn2.

### 3.2 Lower roller driven power

Lower roller driven power is:

In the above formula:

• P – Driven power (m • KW)
• T – Driven force moment (KN • m)
• n2 – Lower roller rotation speed (r • min-1), n2=2V/d2 (V is rolling speed)
• η – transmission efficiency， η=0.65-0.8

The power of the main motor can be obtained from the value of P.

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Author

#### Shane

##### Founder of MachineMFG

As the founder of MachineMFG, I have dedicated over a decade of my career to the metalworking industry. My extensive experience has allowed me to become an expert in the fields of sheet metal fabrication, machining, mechanical engineering, and machine tools for metals. I am constantly thinking, reading, and writing about these subjects, constantly striving to stay at the forefront of my field. Let my knowledge and expertise be an asset to your business.

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